移动端表单提交后提示后跳转到错误页面不知道怎么办了
迅睿框架 更新 2021-10-30 16:20:47
舞台剧
舞台剧
移动端表单提交后，提示后，跳转到错误页面，不知道怎么办了
<form action="" class="my-4" method="post" name="myform" id="myform"> <input name="is_form" type="hidden" value="1"> <input name="is_admin" type="hidden" value="0"> <input name="is_tips" type="hidden" value=""> <input name="csrf_test_name" type="hidden" value="75d111f35943662e52723616577c5c4b"> <li> <input type="text" name="data[author]" id="dr_author" maxlength="20" placeholder="姓名" class="login_input " /> </li> <li> <input type="text" name="data[title]" id="dr_title" maxlength="20" placeholder="手机号码" class="login_input" > </li> <li> <textarea name="content" name="data[neirong]" id="dr_neirong" rows="" onKeyUp="strlen_verify(this,'booklen',255)" placeholder="咨询内容" class="login_textarea" ></textarea> </li> <li> <input class="login_btn common_bg" type="button" onclick="dr_ajax_submit('http://675729.testyuming.top/index.php?s=form&c=ceshi&m=post', 'myform', '2000', 'http://675729.testyuming.top/index.php?s=form&c=ceshi&m=post')" value="提 交"> </li> </form>dr_ajax_submit('/index.php?s=form&c=ceshi&m=post'<input class="login_btn common_bg" type="button" onclick="dr_ajax_submit('http://675729.testyuming.top/index.php?s=form&c=ceshi&m=post', 'myform', '2000', 'http://675729.testyuming.top/index.php?s=form&c=ceshi&m=post')" value="提 交">把后面的http://675729.testyuming.top/index.php?s=form&c=ceshi&m=post改成你想要跳转到的页面链接，看看行不dr_ajax_submit('/mobile/index.php?s=form&c=ceshi&m=post'如果是目录模式的手机端这样