如何防止别人通过ID来采集网站

解决问题：如何防止别人通过ID来采集网站？

1、创建一个fcaiji的字段，以下是代码

{"name":"防采集","fieldname":"fcaiji","fieldtype":"Text","isedit":"1","ismain":"1","issystem":"0","ismember":"1","issearch":"0","disabled":"0","setting":{"option":{"fieldtype":"CHAR","fieldlength":"4","value":"","width":"","css":""},"validate":{"xss":"1","required":"0","pattern":"","errortips":"","check":"","filter":"user_gl_caiji","tips":"","formattr":""},"is_right":"0"},"displayorder":"0"}

2、在custom.php文件中放出以下代码

 function my_cjurl($data) { 

     $url=$data['fcaiji'].$data['id'].'.html';

     return $url;

 }

function my_gl_caiji($value, $data = [], $old = []) {  

      if(empty($value)){

      $characters = 'abcdefghijklmnopqrstuvwxyz';

        $shuffledCharacters = str_shuffle($characters);

        $value = substr($shuffledCharacters, 0, 4);

       }

    return $value; // 返回的数据一定要是字符串格式！！！

}

3、创建URL规则，这里只有独立模块的

{"id":"4","type":"1","name":"防采集","value":"{\"module\":\"{modname}.html\",\"list\":\"{modname}/{dirname}/\",\"list_page\":\"{modname}/{dirname}/{page}/\",\"show\":\"{modname}/{my_cjurl($data)}\",\"show_page\":\"{modname}/{id}_{page}.html\",\"search\":\"{modname}/sch.html\",\"search_page\":\"{modname}/sch-{param}.html\",\"catjoin\":\"/\"}"}

4、在rewrite.php中用如下规则

    "([a-z]+)\/([a-z]+)([0-9]+)\.html" => "index.php?s=$1&c=show&fcaiji=$2&id=$3", 

5、在list.html中用上maxlimit=100的参数

6、在hooks.php中用上如下参数

\Phpcmf\Hooks::app_on('appname', 'module_search_data', function($data) {

     $page=$_GET['page'];

     if($page>5){

          XR_C()->goto_404_page(dr_lang('该分页不存在'));

     }

});

\Phpcmf\Hooks::app_on('appname', 'module_show', function($data) {

    $fcaiji=$_GET['fcaiji'];

    if($data['fcaiji']&&$fcaiji!==$data['fcaiji']){

          XR_C()->goto_404_page(dr_lang('内容不存在！'));

     }

    return dr_return_data(1, '', $data);

});